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## Re: leasqrdemo

**From**: |
Przemek Klosowski |

**Subject**: |
Re: leasqrdemo |

**Date**: |
Thu, 28 Sep 2006 22:57:17 -0400 (EDT) |

I am trying to fit function b*(x^a), but I don't know much about fitting
and I also have problems with derivatives.
I am using leasqrdemo.m, where I defined
p = [-1,10];
....
function y = leasqrfunc(x,p)
y = p(2)*(x^p(1))
endfunction
but I don't know what the leasqrdfdp should look like.
function y = leasqrdfdp(x,f,p,dp,func)
y = [?,?]
endfunction
You don't need to define the derivatives---if you don't they are
calculated numerically. leasqr() is a wonderful facility, but it like
a race car: temperamental and demanding. Still, with little care, it
is a pleasure to drive. Here's a simple example:
x=1:10; y=[12,5,3,2,1,1,1,1,1,1]; p = [-1,10];
function y = leasqrfunc(x,p)
y = p(2)*(x.^p(1))
endfunction
[f,pout]=leasqr(x',y',p,"leasqrfunc");
results in a reasonable fit: pout = [ -1.2841; 12.0054 ]
Note that I changed your function slightly by using the 'scalar'
exponentiation .^ rather than matrix exponentiation, just so that
I can use the function leasqrfunc() on a vector of values, e.g.:
plot(x,y,x,leasqrfunc(x,pout),x,f)
Here's my list of issues with leasqr():
- it seems to be unnecessarily picky about its input arguments: x,y
apparently must be column vectors, as leasqr(x,y,p,"leasqrfunc")
returns an error.
- I can't seem to get it to run quietly: it produces output even
with a semicolon at the end of the command line.
- the help text is exhaustive but not beginner-friendly; leasqrdemo()
didn't help me either
I think that leasqr() is an important Octave facility, and I would be
glad to do some work on it. Is there someone else who likes it too, to
discuss what needs done and how? I haven't used leasqr() that much, so
maybe I am missing something.

**leasqrdemo**, *Petr Šimon*, `2006/09/28`
**Re: leasqrdemo**,
*Przemek Klosowski* **<=**