floor()

[John W. Eaton]

On 28-Sep-2006, shoker_17 wrote:

| 
| Octave Version:  2.1.72
| Knowledge of Octave: Beginner
| 
| ############### matrix of an image#######################
| 1 1 1 1 1 1 1 1 1 1
|  1 1 1 1 1 1 1 1 1 1
|  1 1 1 1 1 1 1 1 1 1
|  0.996078431372549 0.980392156862745 0.992156862745098 1 1 1 1 1 1 1
|  1 0.556862745098039 0.733333333333333 0.733333333333333 0.733333333333333
| 0.733333333333333 0.733333333333333 0.737254901960784 0.729411764705882
| 0.996078431372549
|  1 1 1 1 1 1 1 1 1 1
|  1 1 1 1 1 1 1 1 1 1
|  1 1 1 1 1 1 1 1 1 1
|  1 1 1 1 1 1 1 1 1 1
|  1 1 1 1 1 1 1 1 1 1
| ############### matrix of an image#######################
| 
| The above matrix was used during image floor() computation. When I used
| floor() to round down the decimal values, I got the following result which
| is not what I wanted.
| 
| ############### result#######################
|  1 1 1 1 1 1 1 1 1 1
|  0 0 0 0 0 0 0 0 0 0
|  0 0 0 0 0 0 0 0 0 0
|  0 0 0 1 1 1 1 1 1 1
|  1 0 0 0 0 0 0 0 0 0
|  0 0 0 0 0 0 0 0 0 0
|  0 0 0 0 0 0 0 0 0 0
|  1 1 1 1 1 1 1 1 1 1
|  1 1 1 1 1 1 1 1 1 1
|  0 0 0 0 0 0 0 0 0 0
| ############### result#######################
| 
| Its not difficult for us to see that the result does not tally with the
| original image.
| Anyone faced this problem before?? Please enlighten me!!
| 
| H E L P!

What are you using to display the values above?  It doesn't look like
Octave's default output format.

Try subtracting 1 from your image and see if maybe the display of the
values is rounding to 1 when they are not really exactly 1.

jwe