Re: histc in Octave?

[Aakash Dalwani]

Francesco Potorti` wrote:
> I had made a trivial error.  I wrote this:
>   
> > >     freq(i,:) = sum (y <= x(i) && y < x(i+1));
> > >       
> but I should have written this:
>   
> > >     freq(i,:) = sum (x(i) <= y && y < x(i+1));
> > >       

this still doesn't work.

I couldn't figure out what is causing the error, (I am not working on it 
anymore)

But there is certainly 1 correction that needs to be made:

Instead of: n = rows (x) - 1;

It should be: n = rows (x)

And the for loop should run from 1 to n-1

i.e. instead of: for i = 1:n

It should be: for i=1:n-1

These corrections still dont give the correct answer except for the 
correct value for the last column.

Thanks for your guidance,
Regards,
A