Re: load command question

[Quentin Spencer]

Stefan van der Walt wrote:

> On Sun, May 07, 2006 at 07:04:43PM -0500, Quentin Spencer wrote:
>  
>
> > Myriam Abramson wrote:
> >
> >    
> >
> > > How do I load a file with a variable name?
> > >
> > >
> > > octave> mypattern
> > > mypattern = random4.out
> > > octave> mypattern
> > > mypattern = random4.out
> > > octave> load mypattern
> > > error: load: couldn't open input file `mypattern'
> > > octave> load "mypattern"
> > > error: load: couldn't open input file `mypattern'
> > > octave> 
> > >      
>
> A useful trick is to build command lines from strings.  For example,
> if you have
>
> x = "1"
> filename = "myfile"
>
> you can do
>
> exec(["load(", filename, x, ".dat)"])
>
> which will execute
>
> load(myfile1.dat)
>  

You can also do things like this with sprintf, which I think gives even 
more flexibility:

x="1";
filename="myfile";
load(sprintf("%s%s.dat",filename,x));

or

x=1;
filename="myfile";
load(sprintf("%s%i.dat",filename,x));



Quentin