[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
Re: load command question
|
From: |
Stefan van der Walt |
|
Subject: |
Re: load command question |
|
Date: |
Mon, 8 May 2006 02:49:34 +0200 |
|
User-agent: |
Mutt/1.5.11 |
On Sun, May 07, 2006 at 07:04:43PM -0500, Quentin Spencer wrote:
> Myriam Abramson wrote:
>
> >How do I load a file with a variable name?
> >
> >
> >octave> mypattern
> >mypattern = random4.out
> >octave> mypattern
> >mypattern = random4.out
> >octave> load mypattern
> >error: load: couldn't open input file `mypattern'
> >octave> load "mypattern"
> >error: load: couldn't open input file `mypattern'
> >octave>
A useful trick is to build command lines from strings. For example,
if you have
x = "1"
filename = "myfile"
you can do
exec(["load(", filename, x, ".dat)"])
which will execute
load(myfile1.dat)
Regards
Stéfan