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Re: Forcing Variable Outputs
From: |
Geordie McBain |
Subject: |
Re: Forcing Variable Outputs |
Date: |
Wed, 29 Mar 2006 12:20:46 +1000 |
Does this do what you want?
function varargout = fxn1 (varargin)
varargout = fxn2 (varargin{:});
endfunction
function varargout = fxn2 (varargin)
varargout = {varargin};
endfunction
I see:
octave2.9:1> a = fxn1 (1)
a = 1
octave2.9:2> [a, b] = fxn1 (1, 2)
a = 1
b = 2
On Tue, 2006-03-28 at 20:53 -0500, Bill Denney wrote:
> I have a function that I want to force to have a variable number of output
> arguements based on its calling function's number of output arguements.
> In other words, I want to do something like
>
> function [varargout] = fxn1(varargin)
>
> varargout{:} = fxn2(varargin{:});
>
> endfunction
>
> and I want fxn2 to see the same number of output arguements that fxn1
> sees.
>
> I thought of initializing varargout like
>
> varargout = cell(1, nargout);
>
> but that didn't work. Is there a way to do this?
>
> Bill
>
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