Re: A thing about exponentials.

[Dmitri A. Sergatskov]

Jordi Gutierrez Hermoso wrote:
> Apologies if this is a FAQ, but I couldn't find it in the FAQ, and I
> tried a few searches in the mailing list archive to no avail.
>
> In Octave 0^(1+i) is 0 and 0^i is NaN. They're both NaN in Matlab.

For Octave, the result would depend on underlying C library. On my computer,
both 0^(i) and 0^(1+i) equal zero, is it (IMHO) should be.


> Thanks!
> - JGH

Sincerely,

Dmitri.



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