Re: plotting even function

[Mike Miller]

On Sun, 20 Mar 2005, Geraint Paul Bevan wrote:

> $ g++ a.cc && ./a.out
> +1^2.0  1
> - -1^2.0        1
> +1^0.5  1
> - -1^0.5        nan
>
> As you can see from the results above, the double version of pow cannot 
> cope with a negative base and non-integer exponent. Therefore in this 
> case Octave uses the Complex (i.e. complex<double>) version of pow. It 
> is this routine which is finding complex solutions for negative x 
> instead of the real root that would be required for symmetry about the 
> y-axis.


That's a very complete answer!  Thanks.

Mike



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