Re: Filtering

[Laurent Jacques]

On Monday 28 February 2005 14:24, Hamish Allan wrote:
| octave:4> ans2 = [0 1 1 1 1]
| ans2 =
|
|    0  1  1  1  1
|
| octave:5> x(ans2)
| error: invalid vector index = 0
| octave:5>
|
| Why is this? How else might I achieve what I want to do, which is:

I think that this is incorrect too in matlab since the vector used as index 
for an other vector must be boolean.

Try 
        x(ans2 == 1)
and it will possibly work (not tested).

Laurent.




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