Octave's eval function

[E. Joshua Rigler]

The following does what I want:

  out=eval("if (~exist('tmp')) tmp=0; endif; tmp=tmp+1; tmp*5;");

...specifically, it evaluates the string to 1) initialize the variable
tmp if it doesn't already exist; 2) increment tmp by 1 each time it is
called; and 3) return tmp*5 to the variable out.

Is the fact that eval appears to always return the result of the last
expression in the string (i.e., tmp*5) strictly intentional?  I can't
really tell from the help file.  This is exactly what I want, but I just
want to be sure this behavior isn't likely to change anytime soon.

I'm running 2.1.64 with the latest Forge.  Thanks,

EJR



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