Re: Finding peaks/max in a graph

[John W. Eaton]

| David Bateman David dot Bateman at motorola dot com wrote:
| 
| :> a = [1 2 3 4 5 4 3 2 1 2 3 2 1]';  n = length(a);
| :> peaks = find([a(2:n,1) - a(1:n-1,1) < 0; 1] & [1; a(1:n-1,1) - a(2:n,1)  
<0])
|    peaks =
|       5
|       11
| 
| Just a small remark:
|
| [...]

This message was really from address@hidden, the From: line in
the header was munged when I forwarded the message to the list.

jwe



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