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Small problem in a if condition
From: |
Pol |
Subject: |
Small problem in a if condition |
Date: |
Sun, 1 Feb 2004 15:09:14 +0100 |
Hi there,
I'm trying to convert that script from matlab to octave and I'm hurting
my head on that script:
function zp = kzp(v,z,i)
if (v == '?')
d = z*i ;
endif
if (z == '?')
d = v/i ;
endif
if (i == '?')
d = v/z ;
endif
M = norm(d) ;
P = angle(d)*180/pi ;
zp=[M;P];
endfunction
And now the errors:
octave:1> kzp(1,'?',3)
error: invalid conversion from string to real matrix
error: type conversion failed for binary operator `=='
error: evaluating binary operator `==' near line 7, column 7
error: if: error evaluating conditional expression
error: evaluating if command near line 7, column 1
error: called from `kzp' in file `/home/pol/.octave/m/kzp.m'
octave:1>
Thx for the help, have a happy sunday all.
-pol-
pgpQdQIqhzZjd.pgp
Description: PGP signature
- Small problem in a if condition,
Pol <=