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Re: Problem in a if condition


From: Pol
Subject: Re: Problem in a if condition
Date: Fri, 30 Jan 2004 14:35:35 +0100

On Fri, 30 Jan 2004 14:10:13 +0100
David Bateman <address@hidden> wrote:

> This is a trick question right?
> 

no it's not a trick I just want octave to print the error then write
nothing.

Here I get 4 errors ... 

maybe it's a trick for you but i'm pretty new and I do my best to
understand it.

Why do I get: error: evaluating if command near line 10, column 3 ?? 

the syntax is correct ... 

 tell me what's wrong.

 -pol-



> > y11=y(1,1);
> > y12=y(1,2);
> 
> y12 = 6
> 
> > y21=y(2,1);
> 
> y21 = 3
> 
> > y22=y(2,2);
> > 
> >   if ( (y12-y21) > 0.00000001 )
> 
> 6 - 3 = 3 > 0.00000001   !!!!
> 
> D.
> 
> -- 
> David Bateman                               
> address@hidden Motorola CRM                               
>  +33 1 69 35 48 04 (Ph) 
> Parc Les Algorithmes, Commune de St Aubin    +33 1 69 35 77 01 (Fax) 
> 91193 Gif-Sur-Yvette FRANCE
> 
> The information contained in this communication has been classified
> as: 
> 
> [x] General Business Information 
> [ ] Motorola Internal Use Only 
> [ ] Motorola Confidential Proprietary



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