[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
## late Re: A Simple Matrix Construction Question

**From**: |
alrl1 |

**Subject**: |
late Re: A Simple Matrix Construction Question |

**Date**: |
Wed, 5 Feb 2003 14:09:42 MET |

Sorry about the delay, but I think my answer worths it:
If you pretend to do the following:
A_mxn = B_mxc .* C_cxn
and C is a 1xn row/column vector, you can do this
A_mxn = B_mxc * diag(C_1xn)
instead of
A_mxn = B_mxc .* C_1xn(1:c,1)
It's the solution to a problem I had some days ago.
>* There is probably a really simple way to do the*
>* following, but I'm suffering from a mental block.*
>* *
>* I have a row array 'Y' of arbitrary length, 1xn.*
>* *
>* I want to create an mxn matrix where all of the rows*
>* are the same as 'Y'.*
>* *
>* Of course, I want to do this without resorting to*
>* loops.*
>* *
>* Thanks in advance.*
>
-------------------------------------------------------------
Octave is freely available under the terms of the GNU GPL.
Octave's home on the web: http://www.octave.org
How to fund new projects: http://www.octave.org/funding.html
Subscription information: http://www.octave.org/archive.html
-------------------------------------------------------------

**late Re: A Simple Matrix Construction Question**,
*alrl1* **<=**