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late Re: A Simple Matrix Construction Question
From: |
alrl1 |
Subject: |
late Re: A Simple Matrix Construction Question |
Date: |
Wed, 5 Feb 2003 14:09:42 MET |
Sorry about the delay, but I think my answer worths it:
If you pretend to do the following:
A_mxn = B_mxc .* C_cxn
and C is a 1xn row/column vector, you can do this
A_mxn = B_mxc * diag(C_1xn)
instead of
A_mxn = B_mxc .* C_1xn(1:c,1)
It's the solution to a problem I had some days ago.
> There is probably a really simple way to do the
> following, but I'm suffering from a mental block.
>
> I have a row array 'Y' of arbitrary length, 1xn.
>
> I want to create an mxn matrix where all of the rows
> are the same as 'Y'.
>
> Of course, I want to do this without resorting to
> loops.
>
> Thanks in advance.
>
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- late Re: A Simple Matrix Construction Question,
alrl1 <=