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## Re: A Simple Matrix Construction Question

**From**: |
Heber Farnsworth |

**Subject**: |
Re: A Simple Matrix Construction Question |

**Date**: |
Thu, 23 Jan 2003 13:27:54 -0600 |

I think the preferred way is
X = Y(:,ones(M,1));
Heber
On Thursday, January 23, 2003, at 12:35 PM, Craig Stoudt wrote:

There is probably a really simple way to do the
following, but I'm suffering from a mental block.
I have a row array 'Y' of arbitrary length, 1xn.
I want to create an mxn matrix where all of the rows
are the same as 'Y'.
Of course, I want to do this without resorting to
loops.
Thanks in advance.
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Octave is freely available under the terms of the GNU GPL.
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Subscription information: http://www.octave.org/archive.html
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