Re: behavior of n++

[Douglas Eck]

Heber Farnsworth wrote:
> There is probably some reason for the following behavior but I can't 
> figure out what it might be.
>
> $ octave -q
> octave:1> n = 0
> n = 0
> octave:2> n++
> ans = 0
> octave:3> n++
> ans = 1
>
> I was expecting that if I set n=0 then n++ would be 1.  Why is this not 
> true?
>
> Heber
>
>
>
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1 ruchetta ~>octave
octave:1> n=0
n = 0
octave:2> n++
ans = 0
octave:3> n
n = 1
octave:7> n=0
n = 0
octave:8> ++n
n = 1

The return value of post-increment is the value before
the incrementation. The return value of pre-increment
is the value after. This seems reasonable enought.
In either case, the variable is incremented... notice the value of n.

Cheers,
Doug

--
Dr. Douglas Eck, http://www.idsia.ch/~doug
Istituto Dalle Molle di Studi sull'Intelligenza Artificiale (IDSIA)
Neural Networks, Rhythm Perception and Production, Dynamical Systems



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Octave is freely available under the terms of the GNU GPL.

Octave's home on the web:  http://www.octave.org
How to fund new projects:  http://www.octave.org/funding.html
Subscription information:  http://www.octave.org/archive.html
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