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## Re: exponential fitting

**From**: |
Gert Van den Eynde |

**Subject**: |
Re: exponential fitting |

**Date**: |
Wed, 4 Sep 2002 16:47:49 +0200 |

On Wed, 4 Sep 2002 16:41:39 +0200
address@hidden wrote:
>* Fine. It's working now, thanks a lot.*
>* *
>* expfit is nice, really. the only two problems are:*
>* 1.) the data is shifted very often, that's why I need the 'c' *
>* {y=a*exp(b*x)+c}. *
expfit will return a term where b = 0 and a is the constant 'c' you're looking
for (exp(0*x) = 1).
>* 2.) expfit doesn't calculate the R^2 for me.*
>* maybe I get rid of these, but if you have already a solution - just tell me.*
expfit returns the root mean square (rms):
sqrt(sum((data(i)-fitting_evaluation(i))**2)), you would want to square this,
no ?
Hope this helps,
Gert Van den Eynde
SCK-CEN
Reactor Physics & MYRRHA Dept
Mol,Belgium
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