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Re: handling NaN

From: John W. Eaton
Subject: Re: handling NaN
Date: Wed, 31 Jul 2002 12:59:34 -0500

On 31-Jul-2002, Ben Harris <address@hidden> wrote:

| Here is how I would solve this problem--one extra line of code, MATLAB
| compatible too:
| octave:14> f = [1 2 3 NaN]
| f =
|     1    2    3  NaN
| octave:15> idx = find(~isnan(f));
| octave:16> max(f(idx))
| ans = 3

But without using loops, is there also a way to do this along a
particular dimension of a matrix when each column/row/etc. may have a
different number of NaNs?


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