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DLF - returning transposed vector

From: Wonkoo Kim
Subject: DLF - returning transposed vector
Date: Wed, 24 Jun 98 00:25:59 -0400

I want to return a row or column vector depending on the vector 
type of an argument to my DLF (dynamically linked function).
I declared "ColumnVector y ..." and then computed for y values.
When returning y to the caller, I wanted to transpose if an input 
argument was a row vector.  But the following always returned a column
vector.  I confirmed that 'if' branched correctly according to the 
input vector type, but either returned the same column vector.  
What was wrong?  

    ColumnVector x = args(0).vector_value();
    ColumnVector y (Ny, 0.0);
    if (args(0).matrix_value().cols() > 1) {
        return octave_value (y.transpose());
    } else {
        return octave_value (y);

Since this DLF code will be called quite a lot, I need a fast code and
so I didn't want to copy to a RowVector.  (Perhaps, is x[] style 
access recommended over x() (or x.elem()) access as well?)


// Wonkoo Kim (address@hidden)

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