Inf/Inf = NaN?

[John Utz]

Hello everybody;

On my fake pentium-100 running FreeBSD-2.2-GAMMA and octave-2.0.5 compiled
with gcc-2.7.2 i get the above result ( Inf/Inf = NaN ). Shouldn't this
equal 1?

        I was thinking of hacking if(a==Inf)&&(b==Inf) result = 1 into my
code, but this is not how i like to work.

note, the specific operation is  (Inf-foo)/(Inf+foo) where foo is a real
positive int. This should be equal to 1, but...does the fact that i am
performing operations on Inf cause the math to "throw up it's hands and
surrender", so to speak?

tnx!

john

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 John Utz       address@hidden
        idiocy is the impulse function in the convolution of life