RE: looking for help with auto creating rules with eval hierarchically

[PATTON, BILLY \(SBCSI\)]

Yes, my logic is wrong but it is where I need to start.
There are 7 flows that I need to attach to _<proj>  Now that I have the
start I can run with it.

I think I'm may be on my way.  

Thanks guys.

-----Original Message-----
From: John Graham-Cumming [mailto:address@hidden On Behalf Of John
Graham-Cumming
Sent: Thursday, March 16, 2006 8:55 AM
To: PATTON, BILLY (SBCSI)
Cc: address@hidden
Subject: Re: looking for help with auto creating rules with eval
hierarchically


PATTON, BILLY (SBCSI) wrote:
> As the best of my understanding of what you sent, ${BB_${proj}}, the
> following should work.
> PROJECTS := lde ldg ldm ldf ldw lbf ldb
> BB_lde := a
> BB_ldg := b c
> BB_ldm := d e f
> BB_ldf := g h i j
> BB_ldw := k l n m o
> BB_lbf := p q r s t u
> BB_ldb := v w x y z aa ab
> 
> .PHONY : all $(addprefix BB_ , ${PROJECTS})

This line will expand to

     .PHONY: all BB_ lde BB_ ldg BB_ ldm BB_ ldf BB_ ldw BB_ lbf BB_ ldb

Firstly there's a space after BB_ which I don't think you want and 
secondly I'm not sure that you mean that BB_lde (for example) is a 
target; isn't it that the things in $(BB_lde) are you targets?



> define bb_template
>  $(1): ; echo $(1)
> endef
> 
> all : $(addprefix BB_ , ${PROJECTS})

So this line is:

     all : BB_ lde BB_ ldg BB_ ldm BB_ ldf BB_ ldw BB_ lbf BB_ ldb

Even if you eliminate the space after the _ and get

     all : BB_lde BB_ldg BB_ldm BB_ldf BB_ldw BB_lbf BB_ldb

Is that really what you want?

> $(foreach proj,$(PROJECTS), $(eval $(call bb_template,$(BB_$(proj)))))

This ends up calling bb_template on each of $(BB_lde), $(BB_ldg), ... 
etc.  If you take, for example, $(BB_ldg) that's b c.  So it does

     $(call bb_template,b c)

which is

     b c: ; @echo b c

Which is then $(eval)ed which means that GNU Make ends up defining the 
following two rules:

     b: ; @echo b c
     c: ; @echo b c

Once again I don't think that's what you intended.  This came about 
because of the elimination of my second foreach loop.

 > But it doesn't.  I get missing seperator pointing to the line after
all:

Probably because you've got a blank link between the all: line and the 
$(foreach ...) line.

John.
-- 
John Graham-Cumming
address@hidden

Home: http://www.jgc.org/
Blog: http://www.jgc.org/blog/

POPFile: http://getpopfile.org/
GNU Make Standard Library: http://gmsl.sf.net/
GNU Make Debugger: http://gmd.sf.net/
Fast, Parallel Builds: http://www.electric-cloud.com/

Sign up for my Spam and Anti-spam Newsletter
at http://www.jgc.org/