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help with $(filter ) in pattern rule prereq
From: |
Asperheim, Eric |
Subject: |
help with $(filter ) in pattern rule prereq |
Date: |
Thu, 21 Mar 2002 14:12:39 -0800 |
All,
I'm trying to use the $(filter ) function in the prereq portion of a pattern
rule. Unfortunately, I can't get this to work due to the handling of the "%"
character. I'm using gmake version 3.79.1 on HPUX platform.
For example,
Makefile
--------------------------
rprereqs := ../../c/v80/dbs/c_1.db ../../a/v80/dbs/a.db ../../b/v80/dbs/b.db
# $(filter %, $(rprereqs))
%.db : $(filter %.db, $(rprereqs))
@ echo "target -> $@"
@ echo "prereq -> $^"
../../%.db :
@ echo "target -> $@"
@ echo "prereq -> $^"
--------------------------
gmake b.db
target -> b.db
prereq ->
fhc2349:easperhe gmake b.db
target -> ../../c/v80/dbs/c_1.db
prereq ->
target -> ../../a/v80/dbs/a.db
prereq ->
target -> ../../b/v80/dbs/b.db
prereq ->
target -> b.db
prereq -> ../../c/v80/dbs/c_1.db ../../a/v80/dbs/a.db ../../b/v80/dbs/b.db
I want the % character in the $(filter ) function to resolve to "b" so that
the I'll get
target -> b.db
prereq -> ../../b/v80/dbs/b.db
But it doesn't. Is there anyway to get the $(filter ) command to do what I
want. Or, another way to get this to work?
Thanks,
Eric
Eric Asperheim - CSE Design Automation
phone: (916) 356-4624
Intel Corporation, FM6-81
fax: (916) 356-3051
1900 Prairie City Rd, Folsom, CA 95630
address@hidden
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- help with $(filter ) in pattern rule prereq,
Asperheim, Eric <=