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Re: [Help-gsl] Target machine defined by gsl-1.15 ? Or by gcc ?


From: Sisyphus
Subject: Re: [Help-gsl] Target machine defined by gsl-1.15 ? Or by gcc ?
Date: Tue, 25 Sep 2012 07:48:50 +1000


----- Original Message ----- From: "Rhys Ulerich" <address@hidden>
To: "Richard Haney" <address@hidden>
Cc: <address@hidden>
Sent: Tuesday, September 25, 2012 2:34 AM
Subject: Re: [Help-gsl] Target machine defined by gsl-1.15 ? Or by gcc ?


Hi Richard,

I did a build of gsl-1.15 using gcc.exe (tdm64-1) 4.6.1 under MSYS, and I used the following command line for configure: ./configure CFLAGS="-g -O2 -march=native -fexceptions" --prefix=/c/gsl-1.15_64_-g_O2 &> gsl-1.15_configure.out
...
...the config.log has the following line in the "Platform" section display:
uname -m = i686

I would have expected something different from 'uname -m'.  But I know
nothing about MSYS.

Do the compilation messages echoed by 'make' omit the -march=native
flag you supplied?

If not, can you compile a small test binary with -march=nature and -S
that should contain, say, SSE instructions and observe them in the
output assembly.

If so, then I'd dig into the reason behind the weird 'uname -m' output.

FWIW my MSYS shell outputs the same for 'uname -m'.
I build both 64-bit and 32-bit versions of gsl-1.15 (both dynamic and static) in that shell and I've not experienced any problems .... but then I also haven't tried supplying the CFLAGS argument that Richard is using. In fact, I don't provide any CFLAGS arg at all. (I think this means that '-g -O2' (as specified by configure script ?) is used.)

Cheers,
Rob



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