RE: [h-e-w] Help with defadvice

[Jeff Paquette]

My elisp is not so good either, but as far as I know, apply breaks a list
apart into separate items, calling the function with the "spread" list as
arguments, while concat does not accept a list:

(apply 'concat '("this " "is " "a " "test"))
"this is a test"

(concat '("this " "is " "a " "test"))

Debugger entered--Lisp error: (wrong-type-argument integerp "this ")
  concat(("this " "is " "a " "test"))
  eval((concat (quote ("this " "is " "a " "test"))))
  eval-last-sexp-1(t)
  eval-last-sexp(t)
  eval-print-last-sexp()
* call-interactively(eval-print-last-sexp)

If you break the list apart and pass each element as an argument:

(concat "this " "is " "a " "test")
"this is a test"

So my guess is that you need the apply call to handle the list of arguments.

--
Jeff Paquette                  direct: (508) 616-4526
Principal Software Engineer    email:  address@hidden
NuGenesis Technologies Corp.   web:    http://www.nugenesis.com


-----Original Message-----
From: Michael R. Wolf [mailto:address@hidden
Sent: Thursday, June 19, 2003 1:11 PM
To: address@hidden
Subject: Re: [h-e-w] Help with defadvice


Jeff Paquette <address@hidden> writes:

> Whoops, it's
>
> (defun run-perl (&rest stmts)
>   (call-process "perl" nil nil nil "-e" (apply 'concat stmts)))

I don't understand elisp enough (I'm a Perl Evangelist) to know why
these are different. Could you help?

 (apply 'concat stmts)
 (concat stmts)

I like the idea of using a 'here file' in elsip to escape into Perl!!!
My Perl is much better than my elsip.

Thanks,
Michael Wolf

-- 
Michael R. Wolf
    All mammals learn by playing!
        address@hidden