Re: How does {x..y} supposed to work?

[Alex fxmbsw7 Ratchev]

also for $'\xff'

On Mon, May 17, 2021, 01:38 Chet Ramey <chet.ramey@case.edu> wrote:

> On 5/14/21 6:33 PM, Mike Jonkmans wrote:
>
> > How about {\x..\y} does an escaped expansion?
> > E.g. {\Z..\a} expands to \Z \[ \\ \] \^ \_ \` \a
> > Or {'x'..'y'} expanding to 'x' ... 'y'
>
> This is a reasonable extension, and would solve the {Z..a} issue.
>
> --
> ``The lyf so short, the craft so long to lerne.'' - Chaucer
>                  ``Ars longa, vita brevis'' - Hippocrates
> Chet Ramey, UTech, CWRU    chet@case.edu    http://tiswww.cwru.edu/~chet/
>
>