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Re: how to export (latex) a image without using figure


From: Juan Manuel Macías
Subject: Re: how to export (latex) a image without using figure
Date: Sun, 04 Apr 2021 13:17:28 +0200
User-agent: Gnus/5.13 (Gnus v5.13) Emacs/27.2 (gnu/linux)

Hi Uwe,

Try:

#+ATTR_LaTeX: :float nil
#+CAPTION: La función  La función  $x^2  e^{-\alpha x} = \frac{1}{\alpha}$, 
$\alpha=-\ln(1-p)$  con $p=0.01$  con $p=0.3$
[[./images/dfp_03.png]]

Best regards,

Juan Manuel 

Uwe Brauer writes:

> Hi 
>
> Currently 
>
> #+CAPTION: La función  La función  $x^2  e^{-\alpha x} = \frac{1}{\alpha}$, 
> $\alpha=-\ln(1-p)$  con $p=0.01$  con $p=0.3$
> #+NAME:   fig:plotcalor23
>
> [[./images/dfp_03.png]]
>
> Gets translated to 
>
> \begin{figure}[htbp]
> \centering
> \includegraphics[width=.9\linewidth]{./images/dfp_03.png}
> \caption{\label{fig:plotcalor23}La función  La función  \(x^2  e^{-\alpha x} 
> = \frac{1}{\alpha}\), \(\alpha=-\ln(1-p)\)  con \(p=0.01\)  con \(p=0.3\)}
> \end{figure}
>
> For reasons that needs a longer explanation I would need.
>
>
>
> \includegraphics[width=.9\linewidth]{./images/dfp_03.png}
> \captionof{figure}{\label{fig:plotcalor23}La función  La función  \(x^2  
> e^{-\alpha x} = \frac{1}{\alpha}\), \(\alpha=-\ln(1-p)\)  con \(p=0.01\)  con 
> \(p=0.3\)}
>
>
> How can this be achieved?
>
> Thanks 
>
> Uwe Brauer 
>
>  
>
>




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