Re: [O] calculating column averages follow up

[Nick Dokos]

Jude DaShiell <address@hidden> wrote:

> I removed a separator line above averages and removed a row with blank 
> fields and ran the calculation on this table and it does have a defective 
> formula but I don't know where the defect is now.
> 
> | Date Stamp             | Systalic | Diastalic | Pulse |   |   |   |   |   | 
>   |   |
> |------------------------+----------+-----------+-------+---+---+---+---+---+---+---|
> | [2011-07-19 Tue 02:26] |      138 |        92 |    74 |   |   |   |   |   | 
>   |   |
> | [2011-07-21 Thu 03:50] |      128 |        79 |    76 |   |   |   |   |   | 
>   |   |
> | [2011-07-20 Wed 04:03] |      130 |        85 |    74 |   |   |   |   |   | 
>   |   |
> | [2011-07-22 Fri 02:33] |      121 |        80 |    79 |   |   |   |   |   | 
>   |   |
> | Averages               |   #ERROR |           |       |   |   |   |   |   | 
>   |   |
> |                        |          |         - |       |   |   |   |   |   | 
>   |   |
> |                        |          |           |       |   |   |   |   |   | 
>   |   |
> #+TBLFM: $2=vmean(@<..@>)
> 

Two problems: 1) you want to set a single cell but the way the formula is 
written
makes it a column formula  and 2) the rows as written include the header line 
and go
all the way to the bottom - assuming you want the two rows after the "Averages" 
row,
you can say

#+TBLFM: @>>>$2=vmean(@<<..@>>>>)

That says "the third row from the bottom in column two is the mean of the rows 
in the
same column, ranging from second from the top to fourth from the bottom".

I thought I could use references relative to @> (e.g. @>-3) but apparently 
that's
not the case:

#+TBLFM: @>>>$2=vmean(@<<..@>-3)

does not work for me.

Nick