Re: Prefer to split along the longest edge

[Eli Zaretskii]

> From: Nicolas Desprès <nicolas.despres@gmail.com>
> Date: Sat, 14 Dec 2024 15:06:40 +0100
> Cc: rudalics@gmx.at, emacs-devel@gnu.org
> 
>  > Because these variables define the minimum size to allow splitting, not 
> the order by which split
>  orientations
>  > are tried.
> 
>  Sorry, I don't understand: does it mean you are unable to change the
>  value of split-height-threshold to cause the function to split
>  horizontally?  If so, can you show a recipe?
> 
> I can by setting split-height-threshold to nil, but then it will never split 
> vertically.

You can also set it to a large enough value, no?

> The current implementation first tries to split vertically. If it fails, it 
> tries to split horizontally then it
> falls back to vertical splitting.
> 
> So to split horizontally, it must first fail to split vertically. 

Yes.

> The default threshold values are fine. I just want the default behavior to 
> try the longest edge first.
> This way when both splitting would have succeeded (according to their 
> respective threshold value) it will
> split first where there is more room.

But N columns are not equivalent to N lines.  IOW, if you have a
window that is (N+1)xN, splitting horizontally is not necessarily TRT.