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Re: inverse of add-to-list: remove-from-list
From: |
Boruch Baum |
Subject: |
Re: inverse of add-to-list: remove-from-list |
Date: |
Tue, 13 Oct 2020 16:07:18 -0400 |
User-agent: |
NeoMutt/20180716 |
On 2020-10-13 22:01, Andreas Schwab wrote:
> On Okt 13 2020, Boruch Baum wrote:
>
> >> On Okt 13 2020, Uwe Brauer wrote:
> >> > But there is, as far as I know, no inverse functionality
> >
> > 1] Similar to what Andreas suggested, try this:
> >
> > (let ((aa '(1 2 3 1 4 1 2)))
> > (delete 2 aa)
> > aa)
> >
> > And note that the fine distinction made in the docstring for the
> > `delete' function:
> >
> > "If SEQ is not a list, deletion is never performed destructively;
> > instead this function creates and returns a new vector or string.
> >
> > Write ‘(setq foo (delete element foo))’ to be sure of correctly
> > changing the value of a sequence ‘foo’.
> >
> > So, in the case of SEQ being a list, there is no need to `setq foo'.
>
> This is not true.
Oops. You're correct...
> If the element to delete is the first element of the list, it returns
> the cdr of the list.
... but to quibble, that's not exactly what I'm getting
(let ((aa '(1 2 3 1 4 1 2)))
(delete 1 aa)
aa)
returns (1 2 3 4 2), so it seems to destructively modify the cdr of the
list.
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