Re: Why is FUNC in cl-callf not allowed to be an expression?

[Michael Heerdegen]

Stefan Monnier <address@hidden> writes:

> > My second point in this message: thinking once more about callf, we
> > could also support a syntax like (callf (with EXPR) PLACE ARG) or
> > something like that to support expressions as first arg.
>
> You can already do that, except that `with` is spelled `lambda (it)`:
>
>     (cl-callf (lambda (it) EXPR) PLACE)

Sorry that I haven't been clear: I want EXPR to eval to the function to
be applied, not to the expression to set to.  Like in

  (cl-callf (with (if flag #'1+ #'1-)) my-number)

That's something I occasionally wanted.  Yes, I know I can paraphrase
this with cl-flet.  It's still disappointing that cl-callf can't do it
out of the box.


Michael.