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Re: process the output of $() with files with spaces
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From: |
Bernhard Voelker |
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Subject: |
Re: process the output of $() with files with spaces |
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Date: |
Mon, 19 Aug 2013 22:27:38 +0200 |
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User-agent: |
Mozilla/5.0 (X11; Linux x86_64; rv:17.0) Gecko/20130329 Thunderbird/17.0.5 |
On 08/19/2013 10:14 PM, Bob Proulx wrote:
> Bernhard Voelker wrote:
>> $ printf "%s\0" *.pdf | sort -zV | xargs -0 cat
>
> It may be the same thing but as a matter of taste I prefer 'find'.
>
> find . -maxdepth 1 -name '*.pdf' -print0 | sort -zV | xargs -0 cat
+1
as find(1) offers even more options to restrict the output
to the desired files, e.g. using "-type f" etc.
... depends on the exact use case.
Have a nice day,
Berny