[Bug-wget] [bug #51181] Unexpected "Redirecting output to 'wget-log'."

[Peter Wu]

Follow-up Comment #13, bug #51181 (project wget):

I can only reproduce it with fork before execve *and* when using the "timeout"
command:

#include <unistd.h>
#include <stdio.h>
#include <sys/wait.h>

int main() {
    char *args[] = {
        "timeout", "-k", "26s", "25s",
        "wget", "-O", "test.html", "http://example.com";, NULL
    };
    int pid = fork();
    if (pid < 0) {
        perror("fork");
        return 1;
    } else if (pid == 0) {
        execvp(args[0], args);
        perror("execvp");
        return 1;
    } else {
        wait(NULL);
        perror("wait");
    }
    return 0;
}

It appears that "timeout" is creating a new process group:

977           if (foreground_pgrp != -1 && foreground_pgrp != getpgrp ())
(gdb) p foreground_pgrp
$4 = 12905   # pidof wrapper
(gdb) p (int)getpgrp()
$5 = 12906   # pidof timeout

Suggested workarounds:
- Use "timeout --foreground" or,
- Add the "-o-" option to "wget" to force logging to stdout.

Given the special behavior of "timeout", isn't this "working as intended"?

    _______________________________________________________

Reply to this item at:

  <http://savannah.gnu.org/bugs/?51181>

_______________________________________________
  Message sent via Savannah
  https://savannah.gnu.org/