using-declaration visibility with dependent base-class

[chombier]

Hello,

I think i found a bug in gcc 4.3.2. The following code sample should
not compile, though it does:


template<class T>
class A {

public:
  int foo();

};

template<class T>
class B : protected A<T> {   // also works with private inheritance

protected: // also with private:
  using A<T>::foo;   // this injects A<T>::foo into the scope, so
B<T>::foo should be protected, right ?

};


int main ( int, char**) {

  B<int> bar;

  bar.foo();  // shouldn't compile: foo is protected

  return 0;
}


It seems that the using-declaration makes A<T>::foo public no matter
what.
When A and B are regular non-template classes however, the behavior is
correct.

Best regards,


Max