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Re: [Bug-gnubg] Re: more on bearoff databases
From: |
Joern Thyssen |
Subject: |
Re: [Bug-gnubg] Re: more on bearoff databases |
Date: |
Sun, 27 Oct 2002 19:52:52 +0000 |
User-agent: |
Mutt/1.4i |
On Sun, Oct 27, 2002 at 01:21:04PM -0600, Neil Kaz wrote
> New comments prefaced by (KAZ)
> ----- Original Message -----
> From: "Joern Thyssen" <address@hidden>
> To: "Neil Kaz" <address@hidden>
> Cc: "GNU Backgammon Bugs" <address@hidden>
> Sent: Sunday, October 27, 2002 1:06 PM
> Subject: Re: [Bug-gnubg] Re: more on bearoff databases
> >
> > Unfortunately there are 10M positions with 13 chequers on 13 points, and
> > 15 positions with 2 chequers on five points, hence a total of 150M
> > positions.
>
> (KAZ) OK I was afraid of something like that so lets just stop at the 13
> point !
>
> > > (NK) I don't see how a normal distribution can pick up on wastage
> effects
> > > or tell GNU how to properly play during the bear in.
> >
> > I keep the mean and the variance for the roll distribution, so I think
> > wastage effects are accounted for.
>
> (KAZ) I think I misunderstood. I trust that this is from a database ? I'm
> confused here.
In the normal one-sided bearoff databases we store an array of
probabilities: the probability to bear off in 0 moves, in 1 move, in 2
moves etc etc.
For example,
GNU Backgammon Position ID: qm3bAADMXdsAAA
Match ID : cAkZAAAAAAAA
+13-14-15-16-17-18------19-20-21-22-23-24-+ O: gnubg
| O O O O | | O O O O O | 0 points
| O O O O | | O O |
| | | |
| | | |
| | | |
v| |BAR| | (Cube: 1)
| | | |
| | | |
| | | X X |
| X X X | | X X X | On roll
| X X X X | | X X X | 0 points
+12-11-10--9--8--7-------6--5--4--3--2--1-+ X: jth
Evaluator: BEAROFF-OS (10 points)
Player Opponent
Position 3169448 3047100
Bearing off Bearing at least one chequer off
Rolls Player Opponent Player Opponent
2 0.000 0.000 1.080 0.000
3 0.000 0.000 19.255 5.348
4 0.000 0.000 41.138 37.057
5 0.000 0.000 33.840 52.866
6 0.000 0.000 4.475 4.552
7 0.024 0.011 0.208 0.175
8 0.244 0.189 0.003 0.002
9 1.332 1.308 0.000 0.000
10 4.543 4.807 0.000 0.000
11 10.585 11.350 0.000 0.000
12 18.109 19.187 0.000 0.000
13 22.684 23.238 0.000 0.000
14 20.911 20.528 0.000 0.000
15 13.623 12.634 0.000 0.000
16 5.919 5.135 0.000 0.000
17 1.674 1.353 0.000 0.000
18 0.310 0.233 0.000 0.000
19 0.038 0.026 0.000 0.000
20 0.003 0.002 0.000 0.000
The second column is the probabilities for player jth and the third
column for player gnubg. The fourth and fifth columns are for
calculating gammon probabilities.
The problem is that foreach position I have to store, on average, 18
probabilities. If I calculate the mean and the variance for the
distributions above I get:
Bearing off Saving gammon
Player Opponent Player Opponent
Mean 13.142 13.048 4.218 4.569
Var. 1.732 1.694 0.855 0.680
Saving these only requires 4 values per position i.e., I've saved a
factor of four (depends on the precision required). Using normal
distributions with the means and variances above I get a roll
distribution of:
1 0.000 0.000 0.038 0.000
2 0.000 0.000 1.577 0.042
3 0.000 0.000 16.656 3.900
4 0.000 0.000 44.973 41.011
5 0.000 0.000 31.034 48.485
6 0.004 0.003 5.473 6.445
7 0.036 0.034 0.247 0.096
8 0.250 0.247 0.003 0.000
9 1.228 1.261 0.000 0.000
10 4.281 4.497 0.000 0.000
11 10.597 11.218 0.000 0.000
12 18.628 19.564 0.000 0.000
13 23.253 23.854 0.000 0.000
14 20.613 20.334 0.000 0.000
15 12.976 12.119 0.000 0.000
16 5.801 5.050 0.000 0.000
17 1.842 1.471 0.000 0.000
18 0.415 0.300 0.000 0.000
19 0.066 0.043 0.000 0.000
20 0.008 0.004 0.000 0.000
21 0.001 0.000 0.000 0.000
which is sufficiently close to the "exact" distribution above.
In fact, with the "exact" one-sided distribution p=56.6%, whereas the
approximative distribution gives p=56.8%. A rollout gives 56.6%.
Jørn
--
Joern Thyssen, PhD
Vendsysselgade 3, 3., DK-9000 Aalborg, Denmark
+45 9813 2791 (private) / +45 2818 0183 (mobile) / +45 9633 7036 (work)
Note: new mobile number!