list (comma) operator

[john43]

Hi,

The manual says that the list operator evaluates to the value
of its right-most operand. However, I'm seeing the opposite:

$ touch a b
$ find  '(' -name a , -name b ')' -print
./a


>From the manual: (GNU find version 4.1)

   expr1 , expr2

       List;  both  expr1 and expr2 are always
       evaluated.  The value of expr1 is
       discarded; the value of the list is the
       value of expr2.


-John