Re: date +%s ignores TZ

[Philip Rowlands]

On Fri, 29 Feb 2008, Bob Proulx wrote:

> Jan Engelhardt wrote:
> > I wanted to get the number of seconds since the start of the day.
> >
> >         echo $[`date +%s` % 86400];
> >
> > unfortunately does not do the right thing ÿÿ it would show
> > 82800 instead of 0 when it is (local) midnight.
>
> I can't think of any totally race free way to do this without invoking
> date multiple times.

I might be misunderstanding the problem, but it seems easy enough to do 
this calling date only once:

$ date +%T | awk -F: '{ print $1 * 3600 + $2 * 60 + $3 }'
67652

(corresponding to 18:47:32)


Cheers,
Phil