Re: Number with sign is read as octal despite a leading 10#

[Greg Wooledge]

On Tue, Jul 10, 2018 at 11:00:36AM -0400, Chet Ramey wrote:
> On 7/9/18 9:24 PM, Isaac Marcos wrote:
> 
> > Bash Version: 4.4
> > Patch Level: 12
> > Release Status: release
> > 
> > Description:
> > A value inside an arithmetic expansion is processed as octal despite using
> > a 10# preffix.
> 
> An integer constant cannot contain a `+'.
> 
> > 
> > Repeat-By:
> >         $ echo $((10#+0034))
> >         28
> 
> If anything, this is bash being too liberal in accepting constants that
> begin with `base#'. There would be a good case for rejecting the `10#'
> because it's missing the value.

It also happens with negative values.  I wish the original poster had
shown that case as well.

wooledg:~$ n=-019; echo "$((10#$n))"
bash-5.0: 10#-019: value too great for base (error token is "019")