Re: ``read -N n -t timeout'' saves partial input only when EOF is seen?

[L A Walsh]

isabella parakiss wrote:
> that's not true https://gist.github.com/fa4efd90376ff2714901e4429fdee734
> read successfully reads the data, but then it's discarded by bash
>   
----
   It's discarded by bash because the read doesn't read 10
characters within the time limit.  If you use -N 5, you get
your output.   "-t" says it will timeout and return failure if a
specified number of characters is not read within timeout period.
If timeout is exceeded, then return status is > 128:

bash -c '( printf 12345; sleep 2 ) | ( read -t 1 -N 10 v; echo "s=$?, 
<$v>" )'
s=142, <>

(status is > 128)

>