Re: forked before bash subshell

[L. A. Walsh]

XiaoBing Jiang wrote:
> Thank you for your explain!
>  
>
>     #!/bin/bash
>     (cd /tmp && exec sleep 20) &
>     echo "end"
>
>     Then, instead of having:
>
>     $ ./foo
>     end
>     $ ps f -t pts/5
>       PID TTY      STAT   TIME COMMAND
>      7287 pts/5    Ss     0:00 bash
>     20165 pts/5    R+     0:00  \_ ps f -t pts/5
>     20160 pts/5    S      0:00 /bin/bash ./foo
>     20161 pts/5    S      0:00  \_ sleep 20
----
When I run your program, I get:

>  ./foo; ps f -t pts/3
end
 PID TTY      STAT   TIME COMMAND
91677 pts/3    Ss     0:00 -bash
96604 pts/3    R+     0:00  \_ ps f -t pts/3
96603 pts/3    S      0:00 sleep 20


I don't see a line corresponding to your '/bin/bash ./foo' line.
Isn't my output what you show in the next example?  Is it what was
wanted?

>     You will have:
>
>     $ ./foo
>     end
>     $ ps f -t pts/5
>       PID TTY      STAT   TIME COMMAND
>      7287 pts/5    Ss     0:00 bash
>     20173 pts/5    R+     0:00  \_ ps f -t pts/5
>     20172 pts/5    S      0:00 sleep 20
>
>     This is what you wanted, right?