Re: declare -p doesn't show the global attribute

[Chet Ramey]

On 4/26/15 5:26 PM, isabella parakiss wrote:
> $ fn () { declare -g var=x; declare -p var; } ; fn
> declare -- var="x"
> 
> I think the correct output should be declare -g var="x"
> Is this intended or is it a bug?

There is no such thing as `the global attribute'.  The -g option simply
causes declare to create variables at the global scope instead of in a
function-local scope.  The output you see is no different than what
would have been displayed had `var' been declared and given a value at
the global scope outside the function.

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    chet@case.edu    http://cnswww.cns.cwru.edu/~chet/