declare -gA <Name> does not create globally accessible associative array

[Florian Mayer]

Configuration Information [Automatically generated, do not change]:
Machine: x86_64
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS:  -DPROGRAM='bash' -DCONF_HOSTTYPE='x86_64' 
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='x86_64-pc-linux-gnu' 
-DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL 
-DHAVE_CONFIG_H   -I.  -I../bash -I../bash/include -I../bash/lib  
-D_FORTIFY_SOURCE=2 -g -O2 -fstack-protector --param=ssp-buffer-size=4 -Wformat 
-Wformat-security -Werror=format-security -Wall
uname output: Linux klingon 3.2.0-70-generic #105-Ubuntu SMP Wed Sep 24 
19:49:16 UTC 2014 x86_64 x86_64 x86_64 GNU/Linux
Machine Type: x86_64-pc-linux-gnu

Bash Version: 4.2
Patch Level: 25
Release Status: release

Description:
   The problem is, that declare -gA <NAME> does not create
    a globally accessible object if run from a sourced file inside
   a function.
   (see http://lists.gnu.org/archive/html/bug-bash/2014-05/msg00039.html)

Repeat-By:
   =script init.sh=
   #!/bin/bash

   . foo.sh

   =script foo.sh=
   #!/bin/bash

   init(){
       . bar.sh
       . func.sh
   }
   init
   func_func

   =script bar.sh=
   #!/bin/bash

   # sould declare associative array globally
   declare -gA FOO(
       [FOFU]="42"
   )

   =script func.sh=
   #!/bin/bash

   func_func(){
       # Won't return "42"
       echo ${FOO[FOFU]}
       return 0
   }
  

Fix:
   Add a declare -gA to the beginning of foo.sh
   solves the problem.