Re: IFS handling and read

[Eric Blake]

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According to Юрий Пухальский on 11/26/2009 1:02 PM:
> Good day!
> 
> Theres is a problem with a following code:
> 
> echo a:b|IFS=: read a b; echo $a

This is E4 in the FAQ:
ftp://ftp.cwru.edu/pub/bash/FAQ

POSIX permits, but does not require, that the final element of a pipeline
be executed in a subshell.  Bash uses the subshell, ksh does not.
Variable assignments in a subshell do not affect the parent.

Meanwhile, read obeys IFS according to POSIX, as shown by:

$ IFS=: read a b <<EOF
> 1:2
> EOF
$ echo $a
1

- --
Don't work too hard, make some time for fun as well!

Eric Blake             ebb9@byu.net
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