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Re: problem with echoing script variable to gpg
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From: |
Eric Blake |
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Subject: |
Re: problem with echoing script variable to gpg |
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Date: |
Thu, 18 Dec 2008 12:57:54 -0700 |
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User-agent: |
Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.18) Gecko/20081105 Thunderbird/2.0.0.18 Mnenhy/0.7.5.666 |
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According to pwaugh on 12/18/2008 1:49 AM:
> digest = $( echo -n ${1} | gpg --print-md sha1 )
> echo digest
>
> I do not get the same value!!!! I have no clue why. Help.
Too much whitespace, and a misunderstanding about how shell variables
work. You want:
digest=$( echo -n "$1" | gpg --print-md sha1 )
echo "$digest"
- --
Don't work too hard, make some time for fun as well!
Eric Blake ebb9@byu.net
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Version: GnuPG v1.4.9 (Cygwin)
Comment: Public key at home.comcast.net/~ericblake/eblake.gpg
Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org
iEYEARECAAYFAklKq0EACgkQ84KuGfSFAYCFRgCgpsZf3FyDYGAn4nMaPmqIoxAq
No4Anjl+kNnWGowPn+d8U6vpKSY2OV1Y
=Capc
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