Problem with pattern replacing when STRING is an expandable char

[Heinz-Ado Arnolds]

Configuration Information [Automatically generated, do not change]:
Machine: i686
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS:  -DPROGRAM='bash' -DCONF_HOSTTYPE='i686' 
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i686-pc-linux-gnu' 
-DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL 
-DHAVE_CONFIG_H   -I.  -I/tmp/S/bash-3.2 -I/tmp/S/bash-3.2/include 
-I/tmp/S/bash-3.2/lib   -g -O2
uname output: Linux ***** 2.6.23.1 #1 SMP PREEMPT Tue Oct 16 16:47:14 CEST 
2007 i686 GNU/Linux
Machine Type: i686-pc-linux-gnu

Bash Version: 3.2
Patch Level: 25
Release Status: release

Description:
    Pattern replacing doesn't work like documented with special
    characters "*" and "?" as replacment strings

Repeat-By:
    a=111.1
    echo ${a//[0-9]/x}

    correctly gives "xxx.x", but

    echo ${a//[0-9]/*}

    gives a listing of files in current directory. Seems that the "*"
    is expanded before replacing the pattern.

    It workes the right way at least up to bash-3.1.17(1)-release

    But if you set

    a=111

    it doesn't even work in 3.1.17 right.

Kind regards,

H.-A. Arnolds

--
________________________________________________________________________

Dipl.-Ing. Heinz-Ado Arnolds

MPI fuer Astrophysik
Karl-Schwarzschild-Strasse 1
D-85748 Garching
Phone:  +49/89/30000-2217
FAX  :  +49/89/30000-2388
email:  arnolds[at]MPA-Garching.MPG.DE
________________________________________________________________________