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From: | Matthew Woehlke |
Subject: | Re: Bash getopts option |
Date: | Wed, 28 Feb 2007 10:15:54 -0600 |
User-agent: | Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.8.0.9) Gecko/20061206 Thunderbird/1.5.0.9 Mnenhy/0.7.4.0 |
Shanks wrote:
I am trying to parse command line options using getopts. for parsing options that are words , for e.g -help, Bash is not allowing meto do that. while getopts c:d:fh:help options docase $options in help) echo" Help";; done The above code does not parse -help option. Any suggestions
I don't think getopts knows how to parse words as options (and not as non-GNU-style, certainly). You are probably better off writing your own parser, something like this:
while [ $1 ] ; do [ ${1:0:1} = '-' ] || break case ${1:1} in help) echo help;; c*) if [ ${1:1} ] ; then arg=${1:1} else shift; arg=$1 fi echo "arg of -c is $arg" ;; *) echo "bad option, $1";; esac shift done -- Matthew Obscurity: +5
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