Re: Modifying $0?

[Davy Durham]

Paul Jarc wrote:

> Try this:
> #!/bin/sh
> if [ "$0" != what-you-want ]; then
>  exec /bin/sh -c '. "$@"' what-you-want "$0" ${1+"$@"}
> fi
> shift
> ...
>  
Interesting.. this appears to work.  But I had to remove the shift for 
$1..$n to be correct (even though I see on the 'ps' list that it looks 
as though it needs to have the shift). 

I'm not entirely sure how this is working.  I understand the "$@", but 
does the '-c .' have a special meaning in bash?