decode_prompt_string () bug in octal expansion

[ralph]

Configuration Information [Automatically generated, do not change]:
Machine: i586
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS:  -DPROGRAM='bash' -DCONF_HOSTTYPE='i586' 
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i586-pc-linux-gnu' 
-DCONF_VENDOR='pc' -DSHELL -DHAVE_CONFIG_H  -D_FILE_OFFSET_BITS=64  -I.  -I. 
-I./include -I./lib -I/opt/shells/bash/include -g -O2
uname output: Linux alesaismaphia.myip.org 2.4.0-test12 #6 Thu Dec 21 21:50:42 
CET 2000 i586 unknown
Machine Type: i586-pc-linux-gnu

Bash Version: 2.04
Patch Level: 0
Release Status: release

Description:
        in decode_prompt_string () (file parse.y line 3005) when expanding
        octal sequences, you assume 
        > string += 3;
        if the octal sequence isn't 3 bytes long and the octal is at the end 
        of *string, the end of *string ('\0') is skipped, so the prompt will
        be broken (heap inspection)

Repeat-By:
        export PS1=\\0
        export PS2=\\12
        # any \\octal_numer_with_less_than_3_digits

Fix:
        instead of
        > string +=3;
        i use
        {
          int i=0;
          for (; (*string>='0') && (*string <='7') && i<=2; i++)
            string++;
        }
        
        i check for the lenght of the octal sequence in the next 3 bytes, so i 
        dont't break \0000000.

please reply at <alphanum@libero.it>, otherwise because the dyndns 
when i'm offline points to someone else your reply may not arrive 
to me.

ralph karamanzov -- maphiasoft associated