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Re: [Qemu-devel] [PATCH qemu v2] hmp: Print if memory section is registe


From: Paolo Bonzini
Subject: Re: [Qemu-devel] [PATCH qemu v2] hmp: Print if memory section is registered with an accelerator
Date: Fri, 8 Feb 2019 18:26:34 +0100
User-agent: Mozilla/5.0 (X11; Linux x86_64; rv:60.0) Gecko/20100101 Thunderbird/60.3.1

On 07/02/19 12:49, Dr. David Alan Gilbert wrote:
>  //#define DEBUG_UNASSIGNED
> @@ -2924,6 +2926,8 @@ struct FlatViewInfo {
>      int counter;
>      bool dispatch_tree;
>      bool owner;
> +    AccelClass *ac;
> +    const char *ac_name;
>  };
>  
>  static void mtree_print_flatview(gpointer key, gpointer value,
> @@ -2939,6 +2943,7 @@ static void mtree_print_flatview(gpointer key, gpointer 
> value,
>      int n = view->nr;
>      int i;
>      AddressSpace *as;
> +    bool system_as = false;
>  
>      p(f, "FlatView #%d\n", fvi->counter);
>      ++fvi->counter;
> @@ -2950,6 +2955,9 @@ static void mtree_print_flatview(gpointer key, gpointer 
> value,
>              p(f, ", alias %s", memory_region_name(as->root->alias));
>          }
>          p(f, "\n");
> +        if (as == &address_space_memory) {
> +            system_as = true;
> +        }
>      }
>  
>      p(f, " Root memory region: %s\n",
> @@ -2985,6 +2993,13 @@ static void mtree_print_flatview(gpointer key, 
> gpointer value,
>          if (fvi->owner) {
>              mtree_print_mr_owner(p, f, mr);
>          }
> +
> +        if (system_as && fvi->ac &&
> +            fvi->ac->has_memory(current_machine,
> +                                int128_get64(range->addr.start),
> +                                MR_SIZE(range->addr.size) + 1)) {
> +            p(f, " %s", fvi->ac_name);

I don't understand this.  This doesn't check that the memory range
actually matches the memory registered with the accelerator, only that
there is something in that range.  Why isn't it enough to use "info
mtree" and look at the KVM address space?

Perhaps you could add instead an argument to "info mtree" that prints
only the AddressSpace with a given name?

Paolo



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