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[Help-bash] performance difference between math operations
From: |
Peng Yu |
Subject: |
[Help-bash] performance difference between math operations |
Date: |
Wed, 12 Dec 2018 15:36:50 -0600 |
Hi,
I saw the following performance differences among equivalent math
operations. I ordered them based on their speed. However, the actual
runtime numbers fluctuated. So I am not completely sure the order is
correct. Therefore, knowing the underlying operations may help with
the correct ordering.
What are the underlying machine operations used in each case that can
help determine their performance order?
Can the rest cases be made with performance matching the first case? Thanks.
$ cat main.sh
#!/usr/bin/env bash
# vim: set noexpandtab tabstop=2:
declare -i i
set -v
declare -i n=300000
declare -i x1
time for ((i=0;i<n;++i))
do
x1+=1
done
declare -i x2
time for ((i=0;i<n;++i))
do
x2=x2+1
done
declare y1
time for ((i=0;i<n;++i))
do
((++y1))
done
declare y2
time for ((i=0;i<n;++i))
do
((y2+=1))
done
declare y3
time for ((i=0;i<n;++i))
do
((y3=y3+1))
done
$ ./main.sh
declare -i n=300000
declare -i x1
time for ((i=0;i<n;++i))
do
x1+=1
done
real 0m3.192s
user 0m3.087s
sys 0m0.095s
declare -i x2
time for ((i=0;i<n;++i))
do
x2=x2+1
done
real 0m3.424s
user 0m3.330s
sys 0m0.088s
declare y1
time for ((i=0;i<n;++i))
do
((++y1))
done
real 0m3.459s
user 0m3.363s
sys 0m0.092s
declare y2
time for ((i=0;i<n;++i))
do
((y2+=1))
done
real 0m3.632s
user 0m3.526s
sys 0m0.100s
declare y3
time for ((i=0;i<n;++i))
do
((y3=y3+1))
done
real 0m3.865s
user 0m3.758s
sys 0m0.100s
--
Regards,
Peng
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