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Re: [Discuss-gnuradio] question about set_output_multiple
From: |
dcardona |
Subject: |
Re: [Discuss-gnuradio] question about set_output_multiple |
Date: |
Mon, 15 Jun 2015 08:23:06 -0700 (MST) |
Hello Marcus
Thank you for your response
Before, I was setting the set_output_multiple at the constructor in the .cc
file and i was getting the error I said before
Then, I set it in the .h file and I had no error.
Is it correct to set it in the .h file? Here are both the .cc and the . h
files.
In the .cc file, the set_output_multiple is commented.
Codificador_bf_impl.h
<http://gnuradio.4.n7.nabble.com/file/n54187/Codificador_bf_impl.h>
Codificador_bf_impl.cc
<http://gnuradio.4.n7.nabble.com/file/n54187/Codificador_bf_impl.cc>
Also, I set: int n;
ninput_items_required[0] = noutput_items - n;
at the forecast method. I did this for the reason i explained before; If i
have for example 16 items at the in put, i need to have 16 + n items at the
output. Is this configured right?
Another question: This is about the ninput_items. How should I set it for
my requirements? I suppose this ninput_items should depend of "tamano",
which is the size of the input stream.
Should I use ninput_items instead of tamano in the code? And if this right,
should I set set_output_multiple(int ninput_items + n) instead of
set_output_multiple(int tamano + n)?
PD: In the .cc file you can take a look at the c++ code for the chaotic
coding if you like. And if you are interested, i can send you the c++ code
that gives those values of "zmean3", "zmean6", "secuencias3" and
"secuencias6" and the paper where the theory of this coding method is
specified.
Thank you very much.
David
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